Question

What is the completely factored form of 3x^2-3x-18? Thanks!

Answer 1

`3(x-3)(x+2)`

Explanation:

Start by factoring out the `3`:

`3(x^2-x-6)`

Now to find the factors of the trinomial in the parentheses we have to think of two numbers that add up to `-1` and multiply to `-6`:

These numbers are: `-3` and `2`

So then factored we have:

`3(x-3)(x+2)`