How do you factor $- 2 x^{2} - 5 x = 0$ $-2x^2-5x=0$ ?

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Answer 1 · 2017-10-11T04:14:47

Factored: $- x (2 x + 5) = 0$ $-x(2x+5)=0$

If you wanted to solve for $x$ $x$ : $x = 0 and - \frac{5}{2}$ $x=0 and -5/2$

Start by factoring out a $- x$ $-x$ on the left side:

$- x (2 x + 5) = 0$ $-x(2x+5)=0$

If you wanted to solve for $x$ $x$ you could set both factors equal to $0$ $0$ :

$- x = 0 \to x = 0$ $-x=0->x=0$

$2 x + 5 = 0 \to x = - \frac{5}{2}$ $2x+5=0->x=-5/2$

How do you factor -2x^2-5x=0−2x2−5x=0-2x^2-5x=0?