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Answer 1 · 2017-10-11T04:37:40

$x^2+y^2-12x-10y+25=0$

The equation of a circle with center $(x_0;y_0)$ and radius r is:

$(x-x_0)^2+(y-y_0)^2=r^2$

Then we get the following equation:

$(x-6)^2+(y-5)^2=6^2$

We would transform it to the standard form

$x^2+y^2+ax+by+c=0$ :

$x^2-12x+cancel36+y^2-10y+25=cancel36$

$x^2+y^2-12x-10y+25=0$