How do you factor #5x^2 - 9x +8#?

1 Answer
Oct 11, 2017

No integer factors

Explanation:

We can check to see if there are any real solutions to this quadratic by plugging into the following formula:

#b^2-4*a*c#

In the quadratic formula, this expression is in a radical (square root). So, if this expression is negative, then we would be taking the square root of a negative number, which is imaginary.

#(-9)^2-4*5*8#
#=81-160#
#=-79#

Thus, there do not exist any real solutions to the quadratic. This means that the quadratic does not have any factors.