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Answer 1 · 2017-10-11T20:14:19

Remember: peroxide comes into play only when you add hydrobromic acid $(H B r)$ $(HBr)$ to an alkene.

So, it does not matter if you use "peroxide" as a catalyst for addition of $H C l$ $HCl$ in an alkene.

Now, bringing all the information into account, the reaction would follow a Markovnikov rule of addition.

Hence, the reaction would be $\to$ $rarr$

$C H_{3} C H C H_{2} + H C l \to C H_{3} C H (C l) C H_{3}$ $CH_3CHCH_2+HClrarrCH_3CH(Cl)CH_3$ .

First of all the $H^{+}$ $H^+$ will attack the double bonded terminal carbon atom.

Then, it will form a relatively stable secondary carbonation.

The $C l^{-}$ $Cl^-$ will then attack the carbonation & form 2-Chloropropane.

Hope it Helps:)