How much heat in kcal does "26.4 g"26.4 g of diethyl ether absorb if it was heated from 12.7^@ "C"12.7∘C to 30.5^@ "C"30.5∘C? The specific heat capacity is "0.895 cal/g"^@ "C"0.895 cal/g∘C in this temperature range.

1 Answer
Gaya3 · Truong-Son N.
Oct 12, 2017

q = "0.421 kcal"q=0.421 kcal

Explanation:

q=mC_P∆T

Here,

  • m="26.4 g", the mass of diethyl ether
  • C_P= "0.895 cal"/("g"cdot^@"C"), its specific heat capacity
  • ∆T=30.5^@ "C" - 12.7^@ "C" = 17.8^@ "C", its change in temperature
  • q=?, its heat flow

So,

q=26.4cancel(g) times 0.895"cal"/cancel(g^@C)times17.8^@cancelC

q="420.6 cal" = ul("0.421 kcal")

Related questions
Impact of this question
1255 views around the world
You can reuse this answer
Creative Commons License