Question

Question #4a756

Answer 1

At equilibrium we have 9 moles of `H_2`, 4 moles of `I_2` and 2 moles of HI.

Explanation:

Always start with the balanced chemical equation. In the gas phase, hydrogen and iodine will produce hydrogen iodide

`H_(2(g))+I_(2(g))rarr2HI_((g))`

This tells us the proportions in which the reactants react.

If we have 10 moles of `H_2` to begin with and 10% reacts (one mole), we finish with `10-1=9` moles of `H_2`.

From the equation, one mole of hydrogen gas reacts with one mole of iodine gas. Therefore, only one mole of iodine reacts and we are left with `5-1=4` moles.

For every mole of hydrogen gas that reacts, two moles of HI are formed. If we started with none, one mole of hydrogen dissociating will result in two moles of HI forming.