Question

How do you graph the inequality `y<=-x^2+5x+6`?

Answer 1

it's a parabola

Explanation:

you can find the x-intercepts using the quadratic equation
`-b+-sqrt((b)^2-4*a*c)/(2*a)`
then find the vertex by using `(-b)/(2*a` and `f((-b)/(2*a))`
Then to solve for the inequality, use the coordinates (0,0) for the x and y points, with your equation
`y ≤ −x^2+5x+6`
you get `0 ≤ 6`
since this is true, the area that contains the coordinate (0,0) is the correct area