Question #9e031

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Answer 1 · 2017-10-12T18:16:05

Answer is 4.

#(1-w+w^2)(1-w^2+w)=?#.

Before going into details, let us get some info on omega.

Omega #(w)# is considered as the cube root of unity.

So, we get #rarr#

#w^3=1#

#:.1+ω+ω^2=0#

#:.1+w^2=-w#.

#:.1+w=-w^2#.

Now coming back to the required expression.

#(1-w+w^2)(1-w^2+w)#

#=(-w-w)(-w^2-w^2)#

#=(-2w)(-2w^2)#

#=4w^3#

#=4xx1#

#=4#. (Answer).

Hope it Helps:)