Question #33ad2

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Answer 1 · 2017-10-13T18:04:25

Let's have a look.

Let the length of each side of an equilateral triangle be $a$ $a$ .

Therefore, area of the triangle is $\to$ $rarr$

$A = \frac{\sqrt{3}}{4} a^{2}$ $A=sqrt(3)/4a^2$ .

Substitute the value of $a$ $a$ by $2$ $2$ & get the desired answer.

Hope it Helps:)

Answer 2 · 2017-10-18T13:57:51

$\sqrt{3}$ $sqrt3$

we could use

$A_(Delta)=1/2 a b sinC$

for an equilateral triangle all interior angles are $60^0$

so we ahve

$A_(Delta)=1/2xx2xx2xxsin60$

$A_(Deta)=2xxsqrt3/2$

$=sqrt3$