Given, [2 root(3)49][5 root(3)7][23√49][53√7]
rArr [2. (49)^(1/3)][5. 7^(1/3)]⇒[2.(49)13][5.713]
rArr 2. 5. (7^2)^(1/3). 7^(1/3)⇒2.5.(72)13.713
rArr 10. 7^(2/3).7^(1/3)⇒10.723.713 [ As (a^m)^n = a^(mn)](am)n=amn]
rArr 10. 7^(2/3+1/3)⇒10.723+13 [ As a^m. a^n = a^(m+n)]am.an=am+n]
rArr 10. 7^[(2+1)/3]⇒10.72+13
rArr 10. 7^(3/3)⇒10.733
rArr 10. 7^1⇒10.71
rArr 10. 7 ⇒10.7 [ As a^1 = aa1=a]
rArr 70⇒70