#1.# Convert percentages into moles assuming that 100g of that substance is present
#color(red)(C=60.33%=60.33g )" (in 100g of that substance)"#
#color(red)(=(60.33g)/(12g/"mol")=5.0275"mol"#
#color(blue)(H=5.06%=5.06g#
#color(blue)(=(5.06g)/(1.007g/"mol")=5.024"mol"#
#color(violet)(N=7.82%=7.82g#
#color(violet)(=(7.82g)/(14g/"mol")=0.5586"mol"#
#color(orange)(O=26.79%=26.79g#
#color(orange)(=(26.79g)/(16g/"mol")=1.6744"mol"#
#2.# Divide by the lowest number
# C->color(red)(5.0275/0.5586~~9#
#H-> color(blue)(5.024/0.5586~~9#
#N->color(violet)(0.5586/0.5586=1#
#O->color(orange)( 1.6744/0.5586~~3#
#3.# Write the empirical formula
#color(red)( C_9)color(blue)( H_9)color(violet)( N_1)color(orange)( O_3)#
#=color(red)( C_9)color(blue)( H_9)color(violet)( N)color(orange)( O_3)#
