Question

Question #eb60c

Answer 1

`dy/dx=e^(3x-x^3)(3-3x^2)`

Explanation:

The derivative of `e^u`, where `u` is some function of `x`, is `dy/dx=e^u*(du)/dx`.

So, in this case, the derivative is:

`dy/dx=e^(3x-x^3)*d/dx(3x-x^3)`

Simplifying gives:

`dy/dx=e^(3x-x^3)(3-3x^2)`