How do you solve 6yy225+9y5=5y+5?

2 Answers
Oct 19, 2017

y=7

Explanation:

First, we should try to get the common denominator for all of the fractions.

We should know that (y5)(y+5)=y225. Therefore, we multiply the second fraction (9y5) by (y+5) to get (9y+45y225). The third fraction should be multiplied by y5 to make the denominator all the same, so we get: 5y25.

Since all of the denominators are the same, we can ignore them for now to get....

6y+9y+45=5y25.

We subtract 5y on both sides and subtract 45 (in order to find what y is) and combine like terms...

10y=70.

Divide 10 on both sides to get...

y=7

You can plug it in if you want to, and you should get...

3012=52.

If you need me to go through some details, just ask me in the comments.

-Sakuya

Oct 19, 2017

y=7

Explanation:

Notice that the first denominator is y225

This is the same as y252(y5)(y+5) so this is our starting point.

6y(y5)(y+5)+9y5=5y+5

[6y(y5)(y+5)]+[9y5]=[5y+5]

Multiply by 1 and you do not change the value. However, 1 comes in many forms.

[6y(y5)(y+5)]+dd[9y5×1]dd=dd[5y+5×1]

[6y(y5)(y+5)]+[9y5×y+5y+5]=[5y+5×y5y5]

6y(y5)(y+5)dd+d9y+45(y5)(y+5)d=d5y25(y5)(y+5)

Now that the denominators are all the same we can just forget about them. Or, if you wish to be a purist you can say: multiply all of both sides by (y5)(y+5)

6y+9y+45=5y25

Collecting like terms we have:

6y+9y5y=2545

10y=70

divide both sides by 10

y=7