What is the derivative of $y = [(x-2)/k]^(1/2)$ where k is a constant?

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Answer 1 · 2017-10-20T02:10:58

Look below.

where $k!=0$

$dy/dx=1/2[(x-2)/k]^(-1/2)*d/dx((x-2)/k)$

$=1/2[(x-2)/k]^(-1/2)*(1/k)$

$=1/(2sqrt(k(x-2))$

What is the derivative of y = [(x-2)/k]^(1/2)y = [(x-2)/k]^(1/2) where k is a constant?