Question #95639

2 Answers
Oct 21, 2017

6m

Explanation:

When the Kinetic energy has reduced to half, the other part has become gravitational potential energy E_w=mgh=(58,8 J)/2= 29,4 JEw=mgh=58,8J2=29,4J
hence h=E_w/(mg) = (29,4J)/(0,5kg xx 9,8m/s^2)=6mh=Ewmg=29,4J0,5kg×9,8ms2=6m

Oct 21, 2017

6"m"6m

Explanation:

Initial Kinetic Energy ="KE"_i=58.8J=KEi=58.8J

Final Kinetic Energy ="KE"_f=58.8/2=29.4J=KEf=58.82=29.4J

Let's assume that the rest of Kinetic Energy has been converted into Gravitational potential energy.

Initial Gravitational potential Energy ="PE"_i=0J=PEi=0J

Final Gravitational potential Energy ="PE"_f=58.8-29.4=29.4J=PEf=58.829.4=29.4J

We need to know the height color(blue)hh

So, "PE"_f=mgcolor(blue)hPEf=mgh

=>29.4J=0.5"kg"xx9.8m/s^2xxcolor(blue)h29.4J=0.5kg×9.8ms2×h

=>color(blue)h=(29.4J)/(0.5"kg"xx9.8m/s^2)h=29.4J0.5kg×9.8ms2

=>color(blue)h=(29.4cancelN m)/(0.5cancel"kg"xx9.8cancel(m/s^2))

color(blue)h=6m