Question

How do you factor `48x ^ { 4} y ^ { 2} + 243y ^ { 2}`?

Answer 1

`3y^2(16x^4+81)`

Explanation:

To factor the expression, we have to find the common factor first.
The common factor for `48 and 243` is `3`

So, we know that common factor of `48x^4y^2 and 243y^2` is `3y^2`.

Then, we can just take out the common factor as the following:

`48x^4y^2 + 243y^2`
`=3y^2(16x^4+81)`