How do you multiply $(3 x^{2} y^{5}) (2 x^{8} y^{3})$ $(3x ^ { 2} y ^ { 5} ) ( 2x ^ { 8} y ^ { 3} )$ ?

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Answer 1 · 2017-10-22T04:57:56

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$(3 x^{2} y^{5}) (2 x^{8} y^{3})$ $(3x^2y^5)(2x^8y^3)$

$= 3 x^{2} y^{5} 2 x^{8} y^{3}$ $=3x^2y^5 2x^8y^3$

$= 6 x^{2 + 8} y^{5 + 3}$ $=6x^(2+8)y^(5+3)$

$= 6 x^{10} y^{8}$ $=6x^10y^8$

How do you multiply (3x2y5)(2x8y3)(3x ^ { 2} y ^ { 5} ) ( 2x ^ { 8} y ^ { 3} )?