Question #31947

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Answer 1 · 2017-10-23T08:55:30

$x=2$

The equation is $log(3x-5)=log(x-1)$

When the base of the $log$ is same then -->

$log(f(x))=log(g(x))$

$cancel(log)(f(x))=cancel(log)(g(x))$

$f(x)=g(x)$

Therefore

$log(3x-5)=log(x-1)$

$cancel(log)(3x-5)=cancel(log)(x-1)$

$3x-5=x-1$

$3x-x=-1+5$

$2x=4$

$x=4/2$

$x=2$