Question #1100b

1 Answer
Oct 25, 2017

No, #2/sqrt8# is an irrational number.

Explanation:

#2/sqrt8# is an irrational number. The definition of a rational number is a number that is an integer divided by an integer in the form of #p/q# (i.e. #1, 1/2#).

#2/sqrt8# is in the form of #p/q# but #sqrt8# is not an integer, it is a rational number.

So then what is an irrational number? An irrational number is basically when the number gives you an ongoing decimal.
#2/sqrt8=2.8284....#