Question #02e27

1 Answer
Oct 27, 2017

q=12.329kJ

Explanation:

We are going to use the equation q=mc∆T where q is the energy, m is the mass of all liquid, c is the specific heat capacity and ∆T is the change in temperature.

To calculate ∆T you do final temperature minus initial temperature:

∆T = 87-2 -> ∆T = 85˚C

Specific heat capacity of water is 4.18 J Kg^-1 K^-1

Total mass of liquid is 34.7g

Now plug these values into the equation to find q:

q= 34.7*4.18*85 -> q= 12329J

To have it in kJ divide it by a 1000:

12329/1000 =12.329kJ