Question #748b2

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Answer 1 · 2017-10-28T06:02:12

$p=0.00bar(925)$

The probability that the first roll is a 1 is:

$p_1=1/6$

The probability that the second roll is a 2 is:

$p_2=1/6$

The probability that the third roll is grater than 4 is:

$p_3=2/6=1/3$

As the events are independent, we will multiply the probabilities and get:

$p=1/6*1/6*1/3=1/108=0.00bar(925)$