Question

Question #f6828

Answer 1

`"CHCl"`

Explanation:

`1.` Convert percentages into moles assuming that 100g of that substance is present

`color(red)(C=24.77%=24.77g )" (in 100g of that substance)"`

`color(red)(=(24.77g)/(12g/"mol")=2.064color(white)i"mol"`

`color(blue)(Cl=75.15%=75.15g`

`color(blue)(=(75.15g)/(35.5g/"mol")=2.117color(white)i"mol"`

`color(green)(H=2.08%=2.08g`

`color(green)(=(2.08g)/(1g/"mol")=2.08color(white)i"mol"`

`2.` Divide by the lowest number

`C->color(red)(2.064/2.064~~1`

`H-> color(blue)(2.117/2.064~~1`

`Cl->color(green)(2.08/2.064=1`

`3.` Write the empirical formula
`color(red)( C_1)color(blue)( H_1)color(green)( Cl_1)`

`color(red)( C)color(blue)( H)color(green)( Cl)->` webq.org