How do you solve #\frac { 8} { 4x + 5} - \frac { 1} { x } = \frac { 4} { 7x - 1}#?

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Answer 1 · 2017-10-30T16:47:24

follow the procedure below

From LHS,

equate the whole thing to the same denominator :

#xx# by LCM { (4x+5) (x) }

simplifying worked out resulting in:

#(8x -(4x+5))/((4x-5)(x))# = #4/(7x - 1)#

further simplification:

#(8-4x+5)/(4x^2 +5x)# = #4/(7x +1)#

carry out cross multiplication to obtain the two values of x