Solve #(x-2)^3 = x^3 - 2#?

1 Answer
Nityananda
Oct 31, 2017

1

Explanation:

Given,#(x-2)^3=x^3-2#
#rArr x^3-3x^2. 2+3x.2^2-2^3=x^3-2#
#rArr x^3-x^3-6x^2+12x-8+2=0#
#rArr -6x^2+12x-6=0#
#rArr -6(x^2-2x+1)=0#
#rArr x^2-2x+1=0 #[divide both sides by -6]
#rArr (x-1)^ 2 = 0#
#rArr x-1 = 0#[squaring both sides]
#rArr x = 1#

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