How do you find the derivative of $y=ln(tg^3(x/6))$ ?

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Answer 1 · 2017-10-31T10:41:39

i think $t,g$ is constant .
see below.

$dy/dx=1/(tg^3(x/6))*d/dxtg^3(x/6)$

$=1/(tg^3(x/6))*(tg^3)/6$

$=1/x$

How do you find the derivative of y=ln(tg^3(x/6))y=ln(tg^3(x/6))?