Question #b9d1a

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Question #b9d1a

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Answer 1 · 2017-11-03T15:58:11

The arc length is $π$ $pi$ .

Explanation:

Squaring both sides of this equation gives $y^{2} = 1 - x^{2}$ $y^2=1-x^2$ and a little rearrangement shows this to be a circle with centre $(0, 0)$ $(0, 0)$ and radius 1.
The radical sign $\sqrt{}$ $sqrt$ defines only the positive value of the bracket, so we're looking at just the half circle where y is positive.
Using half of $2 π r$ $2pi r$ , we get a result of $π$ $pi$ .

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