Question #02807

1 Answer
F · Ernest Z.
Nov 5, 2017

3.55 L

Explanation:

The molar mass of #MnO_2# is 86.94 g/mol.

Calculating the number of moles of #Cl_2#,

#"moles Cl"_2 = "12.0 g MnO"_2 (("1 mol MnO"_2) / ("86.94 g MnO"_2)) (("1 mol Cl"_2) / ("1 mol MnO"_2))#

#"moles Cl"_2 = "0.1380 mol"#

Assuming that the gas is ideal,

#PV = nRT#

#V = (nRT) / P#

#V = ((0.1380 mol) (0.082056 (L atm)/(mol K))(25 + 273.15)K)/(0.950atm)#

#V = "3.55 L"#

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