How many atoms are of each element are there in 9.8 g of sulphuric acid, G2SO4 ? ( atomic mass, H=1 , S=32 , O=16)

1 Answer
Nov 5, 2017

1.2004*10^23 atoms / mol H
6.022*10^22
atoms / mol S
2.4088*10^23
atoms / mol O*

Explanation:

The molar mass of H_2SO_4 is 98 g/mol.

For H:
9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((2 mol H)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol H))
=1.2004*10^23 atoms / mol H

For S:
9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((1 mol S)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol S))
=6.022*10^22 atoms / mol S

For O:
9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((4 mol O)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol O))
=2.4088*10^23 atoms / mol O