Question

Question #17573

Answer 1

`878.0254mL`

Explanation:

Given:
`P_1=1.05atm*(760mmHg)/(1atm)=798mmHg`
`V_1=770mL`
`T_1=37^oC=310.15K`
`P_2=675mmHg`
`T_2=26^oC=299.15K`
`V_2=?`

Using the combined gas law,
`(P_1V_1)/T_1=(P_2V_2)/T_2`

Rearranging the equation,
`V_2=(P_1V_1T_2)/(T_1P_2)`

Substituting the given values,
`V_2=(798*770*299.15)/(310.15*675)`
`V_2=878.0254mL`