Question #61142

2 Answers
Nov 5, 2017

#8.58 sq. units#

Explanation:

The area of the square with the length #2sqrt10# is:
#(2sqrt10)^2 = 40#

The diameter of the inscribed circle is #2sqrt10#.
The area of the circle can be computed as:
#A=(pid^2)/4#
#A=(pi(2sqrt10)^2)/4#
#A=10pi=31.42#

Subtracting the area of the circle from the area of the square.
#40 -31.42#
#8.58 sq. units#

Nov 5, 2017

Given, that the side of the square is #s = 2sqrt10# ft, then the radius of the circle is #r = sqrt10" ft"#.

The area of the square is:

#A_"square" = s^2#

#A_"square" = (2sqrt10" ft")^2#

#A_"square" = 40" ft"^2#

The area of the circle is:

#A_"circle" = pir^2#

#A_"circle" = pi(sqrt10" ft")^2#

#A_"circle" = 10pi" ft"^2#

The area not covered is:

#A = A_"square" - A_"circle"#

#A = 40" ft"^2 - 10pi" ft"^2#