Question #29ab3

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Question #29ab3

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Answer 1 · 2017-11-06T03:17:18

$y = - 3 x - 7$ $y=-3x-7$

Explanation:

Determining the slope of the line,
$- x + 3 y = 9$ $−x+3y=9$
$3 y = x + 9$ $3y=x+9$
$y = \frac{1}{3} x + 3$ $y= 1/3x +3$
$m = \frac{1}{3}$ $m=1/3$

We know that the slope of the line perpendicular to $- x + 3 y = 9$ $−x+3y=9$ is equal to its the negative reciprocal of $\frac{1}{3}$ $1/3$ .
Therefore the slope of the unknown line is -3.

Determining the equation of the line passing through $(- 3, 2)$ $(-3,2)$ ,
$(y - y_{1}) = m (x - x_{1})$ $(y-y_1)=m(x-x_1)$
$(y - 2) = - 3 (x - (- 3))$ $(y-2)=-3(x-(-3))$
$y - 2 = - 3 x - 9$ $y-2=-3x-9$
$y = - 3 x - 9 + 2$ $y=-3x-9+2$
$y = - 3 x - 7$ $y=-3x-7$

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Question #29ab3

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