Question #1385b

2 Answers
Nov 6, 2017

The answer is 1.

Explanation:

Since we know #i = sqrt(-1)#, we can say #i^2 = -1#. By this logic, we can separate #i^56# into #(i^2)^28#, which simplifies into #(-1)^28#, or simply #1#.

Nov 6, 2017

#1#

Explanation:

remember that

#i=sqrt(-1), i^2=-1,i^3=-i,i^4=1#

so we look for multiples of #4# in order to simplify the problem simplify the problem

#i^(56)=i^(4xx14)#

#=(i^4)^56#

#=1^56=1#