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Question #04ef8

1 Answer

F · Anwar Hussain

Nov 6, 2017

$130.2 m o l H_{2}$ $130.2molH_2$

Explanation:

The balanced chemical reaction can be written as:
$4 H_{2} + C O_{2} \to C H_{4} + 2 H_{2} O$ $4H_2+CO_2toCH_4+2H_2O$ m

From above reaction,

4 mols $H_{2}$ $H_2$ produce 2 mols of $H_{2} O$ $H_2O$

Therefore,

$65.1 m o l H_{2} O \cdot \frac{4 m o l H_{2}}{2 m o l H_{2} O}$ $65.1molH_2O*(4molH_2)/(2molH_2O)$
$= 130.2 m o l H_{2}$ $=130.2molH_2$

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