Question

Question #291b1

Answer 1

Below

Explanation:

Let theta= x

`(1/sin(x)-cos(x)/sin(x))`

=`((1-cos(x))/sin(x))`

Square both numerator and denominator

=`(((1-cos(x))^2)/sin(x)^2)`

Convert `sin^2(x)` to its identity and split the numerator

=`((1-cos(x))(1-cos(x)))/(1-cos^2(x))`

Split the denominator by using diff. of two squares

=`((1-cos(x))(1-cos(x)))/((1-cos(x))(1+cos(x))`

Cancel terms

=`(cancel(1-cos(x))(1-cos(x)))/(cancel(1-cos(x))(1+cos(x))`

End.