How do you solve #37x - 15= 38#?

1 Answer
Nov 6, 2017

#x~~1.4#

Explanation:

In this problem, you're expected to isolate #x# on one side of the equation, and every other aspect of the equation (including a negative, if you end up with a #(-x)# at the end) on the other side of the #=#.

To do this, you use a process called "balancing the equation," which is essentially working backwards with PEMDAS.

The first part, since we're going backwards, is addition or subtraction. We see there is a #-15#, which we can clear from that side by adding #15# to both sides. It looks like this:

#37x-15+15=38+15#

Since #-15+15=0#,

#37x cancel(-15+15)=38+15#

Giving us, after simplifying the right side by adding #38# and #15#:

#37x=53#

Since #x# is being multiplied by 37, the next step we can use working backwards from PEMDAS is division, to cancel out the multiplication. Do this to both sides as well.

#"37x"-:"37"="53"-:"37"#

Simplify.

#x~~1.4#