Question

What is the equation of the line containing the points (-2, 3) and (1, 2)?

Answer 1

`y=(-1/3)x+2.3`

Explanation:

First, we find our slope. Slopes are written in `y` over `x` form, or `"rise"/"run"`. You can easily remember this by thinking you would run across the `x` axis, but you would rise along the `y` axis.

Slope can be found with the equation `(y_2-y_1)/(x_2-x_1)` Plug the points given into this formula to find your slope.

`(2-3)/(1-(-2)) rArr -1/3`

Draw a graph using your two points given, then use your newfound slope to continue drawing your slope toward the `y` axis until you intersect it. This point will be your `y`-intercept, or `b` in slope-intercept form.

graph{(-1/3x)+2.3 [-11.27, 14.04, -2.82, 9.84]}

This line looks like it hits the `y` axis at about 2.3, so that is your `b`.

Thus, your answer will be `y=(-1/3)x+2.3`