What is the equation of the line containing the points (-2, 3) and (1, 2)?

Question

What is the equation of the line containing the points (-2, 3) and (1, 2)?

1 Answer

Impact of this question

3475 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-07T03:13:17

$y = (- \frac{1}{3}) x + 2.3$ $y=(-1/3)x+2.3$

Explanation:

First, we find our slope. Slopes are written in $y$ $y$ over $x$ $x$ form, or $\frac{rise}{run}$ $"rise"/"run"$ . You can easily remember this by thinking you would run across the $x$ $x$ axis, but you would rise along the $y$ $y$ axis.

Slope can be found with the equation $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$ Plug the points given into this formula to find your slope.

$\frac{2 - 3}{1 - (- 2)} \Rightarrow - \frac{1}{3}$ $(2-3)/(1-(-2)) rArr -1/3$

Draw a graph using your two points given, then use your newfound slope to continue drawing your slope toward the $y$ $y$ axis until you intersect it. This point will be your $y$ $y$ -intercept, or $b$ $b$ in slope-intercept form.

graph{(-1/3x)+2.3 [-11.27, 14.04, -2.82, 9.84]}

This line looks like it hits the $y$ $y$ axis at about 2.3, so that is your $b$ $b$ .

Thus, your answer will be $y = (- \frac{1}{3}) x + 2.3$ $y=(-1/3)x+2.3$

Science

Math

Humanities

... and beyond

What is the equation of the line containing the points (-2, 3) and (1, 2)?

1 Answer

Explanation:

Related questions

Impact of this question