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Question #5c371

1 Answer

Nov 8, 2017

A triangle with $b a s e$ $"base$ =8 and $h e i g h t$ $height$ =4

Explanation:

We know that the area of a triangle is:
$A = \frac{b h}{2}$ $A=(bh)/2$

SInce the area is 16,
$16 = \frac{b h}{2}$ $16=(bh)/2$

Multiplying both sides by 2,
$32 = b h$ $32=bh$

Therefore, all the pairs of numbers with a product of 32 can be the dimensions of the triangle.

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