Question #cb591

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Question #cb591

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Answer 1 · 2017-11-08T01:07:28

$y = \frac{2}{3} x + 3$ $y=2/3x+3$

Explanation:

The slope of the line $y = - \frac{3}{2} x + 11$ $y = -3/2x +11$ is $- \frac{3}{2}$ $-3/2$

Since our unknown line is perpendicular to $y = - \frac{3}{2} x + 11$ $y = -3/2x +11$ , the slope of our unknown is $\frac{2}{3}$ $2/3$ (which is the negative reciprocal of $- \frac{3}{2}$ $-3/2$ ).

The unknown line passes through:
$P_{1} (3, 5)$ $P_1(3,5)$

The equation of the line can be determined using:
$(y - y_{1}) = m (x - x_{1})$ $(y-y_1)=m(x-x_1)$

$(y - 5) = \frac{2}{3} (x - 3)$ $(y-5)=2/3(x-3)$

Simplifying further,
$y - 5 = \frac{2}{3} x - 2$ $y-5=2/3x-2$

$y = \frac{2}{3} x - 2 + 5$ $y=2/3x-2+5$

$y = \frac{2}{3} x + 3$ $y=2/3x+3$

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Question #cb591

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