How do you solve this system of equations: $x - 0.2 y = 0 and 4 x - 8 y = - 4$ $x- 0.2y = 0 and 4x - 8y = - 4$ ?

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How do you solve this system of equations: $x - 0.2 y = 0 and 4 x - 8 y = - 4$ $x- 0.2y = 0 and 4x - 8y = - 4$ ?

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Answer 1 · 2017-11-08T16:44:57

$x$ $x$ = $\frac{1}{9}$ $1/9$ , $y$ $y$ = $\frac{5}{9}$ $5/9$

Explanation:

$x - 0.2 y = 0$ $x-0.2y=0$ ---- 1

$4 x - 8 y = - 4$ $4x-8y=-4$ ---- 2

from equation 1,
$x = 0.2 y$ $x=0.2y$

substitute $x = 0.2 y$ $x=0.2y$ into equation 2
$4 (0.2 y) - 8 y = - 4$ $4(0.2y)-8y=-4$
$0.8 y - 8 y = - 4$ $0.8y-8y=-4$
$- 7.2 y = - 4$ $-7.2y=-4$
$y = \frac{5}{9}$ $y=5/9$

substitute $y = \frac{5}{9}$ $y=5/9$ into $x = 0.2 y$ $x=0.2y$
$x = 0.2 (\frac{5}{9})$ $x=0.2(5/9)$
$x = \frac{1}{9}$ $x=1/9$

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How do you solve this system of equations: $x - 0.2 y = 0 and 4 x - 8 y = - 4$ $x- 0.2y = 0 and 4x - 8y = - 4$ ?

1 Answer

Explanation:

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How do you solve this system of equations: x−0.2y=0and4x−8y=−4x- 0.2y = 0 and 4x - 8y = - 4?

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Explanation:

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How do you solve this system of equations: $x - 0.2 y = 0 and 4 x - 8 y = - 4$ $x- 0.2y = 0 and 4x - 8y = - 4$ ?