How do you solve this system of equations: $x- 0.2y = 0 and 4x - 8y = - 4$ ?

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Answer 1 · 2017-11-08T16:44:57

$x$ = $1/9$ , $y$ = $5/9$

$x-0.2y=0$ ---- 1

$4x-8y=-4$ ---- 2

from equation 1,
$x=0.2y$

substitute $x=0.2y$ into equation 2
$4(0.2y)-8y=-4$
$0.8y-8y=-4$
$-7.2y=-4$
$y=5/9$

substitute $y=5/9$ into $x=0.2y$
$x=0.2(5/9)$
$x=1/9$

How do you solve this system of equations: x- 0.2y = 0 and 4x - 8y = - 4x- 0.2y = 0 and 4x - 8y = - 4?