Find the value of k if the discriminant = 0?

x x^2 -3x+2+1/k=0x23x+2+1k=0

1 Answer
Nov 10, 2017

k=4k=4

Explanation:

The equation is x^2-3x+2+1/k=0x23x+2+1k=0

Here,

a=1a=1 , b=-3b=3 , c=2+1/kc=2+1k

According to the question the discriminant is equal to 00

We know the determinant of a quadratic equation is b^2-4acb24ac

Therefore,

b^2-4ac=0b24ac=0

b^2=4acb2=4ac

Substitute the values of aa , bb and cc

(-3)^2=4 xx 1 xx (2+1/k)(3)2=4×1×(2+1k)

9=8+4/k9=8+4k

9-8=4/k98=4k

1=4/k1=4k

k=4k=4