How do you write x^2 +3x+1/4 in standard form ?

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How do you write x^2 +3x+1/4 in standard form ?

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Answer 1 · 2017-11-11T02:00:43

Standard Form is $a x^{2} + b x + c = 0$ $ax^2 +bx + c = 0$ for quadratic equations .
Standard form for Linear equations are $A x + B y + C = 0$ $Ax + By + C = 0$

so for $x^{2} + 3 x + \frac{1}{4}$ $x^2 +3x+1/4$

Explanation:

A and B are the coefficients to the variables and in standard form C is always without a variable.

Your question is already in standard form the only thing missing is the $= 0$ $=0$

your $a = 1, b = 3, c = \frac{1}{4}$ $a = 1, b= 3, c = 1/4$

$1 x^{2} + 3 x + \frac{1}{4} = 0$ $1x^2 + 3x + 1/4 = 0$

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How do you write x^2 +3x+1/4 in standard form ?

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