How do you solve #- 3( 4r - 8) = - 36#?

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Answer 1 · 2017-11-11T04:56:54

#-3(4r - 8) = -36#

distribute the -3 to the terms in the parentheses

#-12r - 24 = -36#

Isolate the variable by adding #-24# to both sides of the equation

#-12 r = -12#

Divide both sides by a form of one to simplify and isolate variable further

#(-12r)/-12 = (cancel-12)/(cancel(-)12)#

# r = 1 #

check answer

#-3 (4 (1) - 8) = -36 #

#-12 - 24 = -36#

#true#