How do you solve #z( 6z - 5) ( z + 5) = 0#?

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Answer 1 · 2017-11-11T05:43:54

distribute #z# then foil

#z(6z -5 )(z+5) = 0#

distribute z to the first parentheses term

#6z*z = 6z^2#

#(6z^2 -5z)(z+5)#

now we foil ( First - Outside - Inner - Last)

F
#6z^2*z = 6z^3#

O

#6z^2*5= 30z^2#

I
# -5z * z = -5z^2#

L

# -5z * 5 = -25z#

Now we just bring like terms together keep in mind the signs
and the final answer should be

#6z^3 + 25z^2 - 25z#