Question #09f05

1 Answer
Nov 11, 2017

1/((sin2x)/x) is the correct way

Explanation:

When you have a/b it is equivalent to writing 1/(b/a).

This is dividing the numerator and the denominator by the value of numerator.

So \lim_(x\rightarrow 0) (2x)/(sin2x)=\lim_(x\rightarrow 0) 1/((sin2x)/(2x))