How do you factor $- 18 a^{2} b + 50 b$ $-18a ^ { 2} b + 50b$ ?

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Answer 1 · 2017-11-11T21:45:09

Find GCF and factor it out.

$- 18 a^{2} b + 50 b$ $-18a^2b + 50b$

$- 18, 50$ $-18, 50$ have two common factors which is $2$ $2$ and $b$ $b$ and a negative.

$- 2 b (9 a^{2} - 25)$ $-2b(9a^2 - 25)$

as you can see now we have a difference of squares,

$(3 a - 5) (3 a + 5) = (9 a^{2} - 25)$ $(3a -5)(3a+5) = (9a^2-25)$

- $2 b (3 a - 5) (3 a + 5)$ $2b(3a-5)(3a+5)$

The $G C F$ $GCF$ is now 1 and nothing can be furthered simplified.

hope this helps!

How do you factor −18a2b+50b-18a ^ { 2} b + 50b?