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Answer 1 · 2017-11-11T21:54:19

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we want to subtract 61 from both sides to get an inequality with the variable isoloted

$13 x \leq - 61$ $13x<=-61$

now simply divide by a form of one in this case $\frac{13}{13}$ $13/13$

$\frac{13 x}{13} \leq - \frac{61}{13}$ $(13x)/13 <= -61/13$

$x \leq - \frac{61}{13}$ $x <= -61/13$

so $x$ $x$ can only be $- \frac{61}{13}$ $-61/13$ or less

interval notation $(- \infty, - \frac{61}{13}]$ $(-oo, -61/13]$

we use a bracket because its a soft inequality meaning it equals a value too.

set builder would be ${x ∣ x \leq - \frac{61}{13}}$ ${x| x<= - 61/13}$