Question #b68b4

1 Answer
kxoraxe
Nov 12, 2017

y=-x+pi/2y=−x+π2

Explanation:

f(x)=arccos xf(x)=arccosx
f'(x)=-1/sqrt(1-x^2)

h=0
k=f(0)=arccos(0)=pi/2

m=f'(0)=-1/sqrt(1-(0)^2)
=-1/sqrt(1-0)
=-1/sqrt(1)
=-1/1
=-1

y-k=m(x-h)
y-pi/2=-1(x-0)
y=-x+0+pi/2
y=-x+pi/2

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