Question

Question #1e366

Answer 1

Alcoholic `KOH` is mostly used in elimination reactions.

Explanation:

Reason:
Alcoholic `KOH`(mostly having ethanol) produces `C_2H_5O^-` ions which act as a stronger base. So these have the ability to abstract the `beta`- hydrogen from the substrate molecule(alkyl halide), forming alkene as a product. That's the reason behind the statement; Alcoholic `KOH` give elimination reactions.

Example:

`CH_3CH_2Br + KOH(alcoholic) to H_2C=CH_2 + KBR +H_2O`

This is an example of elimination reactions of alkyl halides.

Hope it helps...