How do you find the equation of the parabola given the focus at (0, 2); vertex at (0,0)?

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Answer 1 · 2017-11-13T07:45:26

#x^2=8y#

the parabola equation

#(x-h)^2=4p(y-k)#

where
#V(h,k)#
and
#F(h,k+p)#

then #V(h,k)=V(0,0)#

#F(0,2)#

p=2

in the equation

#(x)^2=4(2)(y)#

#x^2=8y#